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Quantity of electricity (in Coulombs)  

  = Current(I)  x  time(t)

Substituting /converting time to second 

  = 2.5  x (20 x 60)

  = 3000 C

If 3.2g of Lead    ->    3000C

Then 207 g of Lead     ->   207 x 3000

       3.2

   =   194062.5 C

Equation at the cathode:   Pb2+ (l) +  2e   ->   Pb(l)

From the equation:

 2 moles of electrons = 2 Faradays =  194062.5 C

1mole of electrons   =  1 Faraday  => 194062.5

  2

   =  97031.25 C